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Ai(z)Bi0 (z) − Ai0 (z)Bi(z) = π −1 (4.4) by a simple calculation leads to, as shown by Tolmatz [23, Lemma 2.1], see (4.7) below, 27/6 π −1 i Ψ∗ (z) = 0 1/3 2 . (4.5) Ai (2 z) + Bi0 (21/3 z)2 √ It seems simpler to instead consider 2 Bbr…
